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Hugo Santos

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Selection Sort

This sort algorithm has a complexity of O(n²).
For each element in the array the algorithm tries to find the lowest value in the remaining elements of the array. If it finds that lowest value, a swap operation happens. If not, it does nothing and continues. In the end we get an ordered array with less swaps than if we had done the sequential sort [1].

def sel_sort(l):
    n = len(l)
    for i in range(0, n - 1):
        indMin = i
        for j in range(i + 1, n):
            if l[j] < l[indMin]:
                indMin = j
        if indMin != i:
            l[i], l[indMin] = l[indMin], l[i]


l = [10, 45, 4, 5, 2, 10, 1]
print l  # [1, 2, 4, 5, 10, 10, 45]

[1] For each element, if the algorithm finds any lower value, it swaps those values.